The diagram shows triangle ABC - Edexcel - GCSE Maths - Question 7 - 2019 - Paper 1

Question 7

The diagram shows triangle ABC.
ADB is a straight line.
the size of angle DCB : the size of angle ACD = 2 : 1
Work out the size of angle BDC.
Worked Solution & Example Answer:The diagram shows triangle ABC - Edexcel - GCSE Maths - Question 7 - 2019 - Paper 1
Find angle ACD

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To find angle ACD, first note that the angles around point D must sum to 180°. Therefore, we can write:
extAngleACD=180°−75°−51°=54°
Thus, angle ACD is 54°.
Use the ratio to find angle DCB

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The ratio of angle DCB to angle ACD is given as 2:1. Let the size of angle DCB be 2x and the size of angle ACD be x:
extAngleDCB=2x
extAngleACD=x
Given that angle ACD is 54°, we can set up the equation:
x=54°
Thus, substituting this back, we find:
extAngleDCB=2(54°)=108°.
Calculate angle BDC

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Now to find angle BDC, we again apply the angles around point D:
extAngleBDC=180°−(extAngleDCB+extAngleACD)
Substituting the values we have:
extAngleBDC=180°−(108°+54°)=180°−162°=18°.
Therefore, the size of angle BDC is 18°.
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