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For all values of $x$ $f(x) = (x + 1)^2$ and $g(x) = 2(x - 1)$ (a) Show that $g(f(x)) = 2x(x + 2)$ (b) Find $g(7)$ (Total for Question 19 is 4 marks) - Edexcel - GCSE Maths - Question 1 - 2018 - Paper 2

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For-all-values-of-$x$----$f(x)-=-(x-+-1)^2$-and-$g(x)-=-2(x---1)$----(a)-Show-that-$g(f(x))-=-2x(x-+-2)$----(b)-Find-$g(7)$----(Total-for-Question-19-is-4-marks)-Edexcel-GCSE Maths-Question 1-2018-Paper 2.png

For all values of $x$ $f(x) = (x + 1)^2$ and $g(x) = 2(x - 1)$ (a) Show that $g(f(x)) = 2x(x + 2)$ (b) Find $g(7)$ (Total for Question 19 is 4 marks)

Worked Solution & Example Answer:For all values of $x$ $f(x) = (x + 1)^2$ and $g(x) = 2(x - 1)$ (a) Show that $g(f(x)) = 2x(x + 2)$ (b) Find $g(7)$ (Total for Question 19 is 4 marks) - Edexcel - GCSE Maths - Question 1 - 2018 - Paper 2

Step 1

Show that $g(f(x)) = 2x(x + 2)$

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Answer

To find g(f(x))g(f(x)), we first need to substitute f(x)f(x) into the function g(x)g(x).

  1. Start with f(x)=(x+1)2f(x) = (x + 1)^2. This can be expanded to:

    f(x)=x2+2x+1f(x) = x^2 + 2x + 1.

  2. Now, substitute f(x)f(x) into g(x)g(x), where g(x)=2(x1)g(x) = 2(x - 1):

    g(f(x))=2((x+1)21)g(f(x)) = 2((x + 1)^2 - 1)

    This becomes:

    g(f(x))=2(x2+2x+11)g(f(x)) = 2(x^2 + 2x + 1 - 1)

    Simplifying further, we get:

    g(f(x))=2(x2+2x)g(f(x)) = 2(x^2 + 2x)

    Finally, this simplifies to:

    g(f(x))=2x(x+2)g(f(x)) = 2x(x + 2)

    Thus, we have shown that g(f(x))=2x(x+2)g(f(x)) = 2x(x + 2).

Step 2

Find $g(7)$

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Answer

To find g(7)g(7), we use the defined function g(x)=2(x1)g(x) = 2(x - 1):

  1. Substitute xx with 7:

    g(7)=2(71)g(7) = 2(7 - 1)

    Simplifying this yields:

    g(7)=2(6)g(7) = 2(6)

    Therefore:

    g(7)=12g(7) = 12

    Thus, the final answer is g(7)=12g(7) = 12.

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