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10 (a) Simplify \( \left( \frac{1}{m} \right)^{y} \) (b) Simplify \( \frac{8(k - 4)}{(k - 4)^{2}} \) (c) Simplify \( (3n^{2}w^{2})^{3} \) - Edexcel - GCSE Maths - Question 11 - 2020 - Paper 2

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Question 11

10-(a)-Simplify-\(-\left(-\frac{1}{m}-\right)^{y}-\)----(b)-Simplify-\(-\frac{8(k---4)}{(k---4)^{2}}-\)----(c)-Simplify-\(-(3n^{2}w^{2})^{3}-\)-Edexcel-GCSE Maths-Question 11-2020-Paper 2.png

10 (a) Simplify \( \left( \frac{1}{m} \right)^{y} \) (b) Simplify \( \frac{8(k - 4)}{(k - 4)^{2}} \) (c) Simplify \( (3n^{2}w^{2})^{3} \)

Worked Solution & Example Answer:10 (a) Simplify \( \left( \frac{1}{m} \right)^{y} \) (b) Simplify \( \frac{8(k - 4)}{(k - 4)^{2}} \) (c) Simplify \( (3n^{2}w^{2})^{3} \) - Edexcel - GCSE Maths - Question 11 - 2020 - Paper 2

Step 1

Simplify \( \left( \frac{1}{m} \right)^{y} \)

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Answer

To simplify ( \left( \frac{1}{m} \right)^{y} ), we apply the power of a fraction rule, which states that ( \left( \frac{a}{b} \right)^{n} = \frac{a^{n}}{b^{n}} ). Thus, we have:

[ \left( \frac{1}{m} \right)^{y} = \frac{1^{y}}{m^{y}} = \frac{1}{m^{y}}. ]

Step 2

Simplify \( \frac{8(k - 4)}{(k - 4)^{2}} \)

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Answer

The expression can be simplified by canceling common factors in the numerator and denominator:

[ \frac{8(k - 4)}{(k - 4)^{2}} = \frac{8}{k - 4}, \ k \neq 4. ]

Step 3

Simplify \( (3n^{2}w^{2})^{3} \)

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Answer

For this expression, we apply the rule ( (ab)^{n} = a^{n}b^{n} ) and also handle the power of a power rule ( (a^{m})^{n} = a^{mn} ):

[ (3n^{2}w^{2})^{3} = 3^{3}(n^{2})^{3}(w^{2})^{3} = 27n^{6}w^{6}. ]

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