The diagram shows two shaded shapes, A and B - Edexcel - GCSE Maths - Question 23 - 2020 - Paper 1
Question 23
The diagram shows two shaded shapes, A and B.
Shape A is formed by removing a sector of a circle with radius $(3x - 1)$ cm from a sector of the circle with radius $... show full transcript
Worked Solution & Example Answer:The diagram shows two shaded shapes, A and B - Edexcel - GCSE Maths - Question 23 - 2020 - Paper 1
Step 1
Derive an algebraic expression for the area of A
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Answer
The area of the sector A can be calculated using the formula for the area of a sector:
A=360θ×πr2
Here, let the angle be (\theta) (in degrees) for the circle with radius (3x - 1) and the angle for the circle with radius (5 - 1 = 4) cm. The formula results in:
A=360θ×π(3x−1)2−360θ′×π(42)
Step 2
Find the area of shape B
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Answer
Shape B is a circle with diameter ((2 - 2) = 0) cm. The radius is therefore:
rB=20=0
Thus, the area of shape B is:
AreaB=πrB2=π(0)2=0
Step 3
Equate the area of shape A to the area of shape B
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Answer
Since the area of shape A is equal to the area of shape B:
A=0
We can simplify the expression we derived for the area of shape A and set it equal to zero.
Step 4
Solve for x
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Answer
After substituting the expressions and simplifying:
Rearranging into a quadratic:
3x2−6x+0=0
Then factor or apply the quadratic formula, using the context of the initial formulation to find:[ x = \frac{6 \pm \sqrt{(6)^2 - 4(3)(0)}}{2(3)} = 2 \text{ or } 0 \text{ (invalid, since } x > 1)$$