Kiaria is 7 years older than Jay - Edexcel - GCSE Maths - Question 2 - 2017 - Paper 1

From the problem, we know that the sum of their ages is 77. Hence, we can write the equation:

$j + (j + 7) + 2(j + 7) = 77$

Simplifying the equation:

$j + j + 7 + 2j + 14 = 77$ $4j + 21 = 77$ $4j = 56$ $j = 14$

Thus, Jay's age is 14.

Now, substituting $j$ back to find Kiaria's and Martha's ages:

• Kiaria's age: $j + 7 = 14 + 7 = 21$
• Martha's age: $2(j + 7) = 2 \times 21 = 42$

Finally, we need to find the ratio of Jay's age to Kiaria's age to Martha's age:

$\text{Ratio} = j : (j+7) : (2(j+7)) = 14 : 21 : 42$

To simplify this, we divide by 7:

$\text{Ratio} = 2 : 3 : 6$