Photo AI

There are only red counters, blue counters and purple counters in a bag - Edexcel - GCSE Maths - Question 16 - 2018 - Paper 1

Question icon

Question 16

There-are-only-red-counters,-blue-counters-and-purple-counters-in-a-bag-Edexcel-GCSE Maths-Question 16-2018-Paper 1.png

There are only red counters, blue counters and purple counters in a bag. The ratio of the number of red counters to the number of blue counters is 3 : 17. Sam takes... show full transcript

Worked Solution & Example Answer:There are only red counters, blue counters and purple counters in a bag - Edexcel - GCSE Maths - Question 16 - 2018 - Paper 1

Step 1

The ratio of red to blue counters is 3:17

96%

114 rated

Answer

Let the number of red counters be represented as 3x and the number of blue counters as 17x, for some positive integer x.

Step 2

Finding the total number of counters in the bag

99%

104 rated

Answer

Let the number of purple counters be y. The total number of counters can be expressed as:

extTotal=3x+17x+y=20x+y ext{Total} = 3x + 17x + y = 20x + y.

Step 3

Calculating the probability of selecting a red counter

96%

101 rated

Answer

The probability of selecting a red counter is given by the ratio of the number of red counters to the total number of counters:

P(extred)=3x20x+yP( ext{red}) = \frac{3x}{20x + y}.

We know that the probability of selecting a purple counter is 0.2, which means:

P(extpurple)=y20x+y=0.2P( ext{purple}) = \frac{y}{20x + y} = 0.2.

From this, we can express y in terms of x:

y=0.2(20x+y)    y=4x+0.2y    0.8y=4x    y=5x1y = 0.2(20x + y) \implies y = 4x + 0.2y \implies 0.8y = 4x \implies y = \frac{5x}{1}.

Now, substituting y back into the probability of selecting a red counter:

P(extred)=3x20x+5x=3x25x=325P( ext{red}) = \frac{3x}{20x + 5x} = \frac{3x}{25x} = \frac{3}{25}.

Join the GCSE students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;