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The diagram shows rectangle STUV - Edexcel - GCSE Maths - Question 8 - 2022 - Paper 3

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Question 8

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The diagram shows rectangle STUV. TQU and SRV are straight lines. All measurements are in cm. The area of trapezium QUVR is A cm² Show that A = 2x² + 20x.

Worked Solution & Example Answer:The diagram shows rectangle STUV - Edexcel - GCSE Maths - Question 8 - 2022 - Paper 3

Step 1

Find the area of rectangle STUV

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Answer

The area of rectangle STUV can be calculated using the formula:

Area=length×width\text{Area} = \text{length} \times \text{width}

Here, the length is 5 cm and the width is 4x cm. Therefore,

Area=5×4x=20x.\text{Area} = 5 \times 4x = 20x.

Step 2

Find the area of triangle TQU

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Answer

The area of triangle TQU can be calculated as follows:

Area=12×base×height\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}

Here, the base is 2x cm and the height is 4 cm. Thus,

Area=12×2x×4=4x.\text{Area} = \frac{1}{2} \times 2x \times 4 = 4x.

Step 3

Find the area of trapezium QUVR

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Answer

To calculate the area of trapezium QUVR, we use the formula:

A=12×(Base1+Base2)×heightA = \frac{1}{2} \times (\text{Base}_1 + \text{Base}_2) \times \text{height}

Here, Base_1 = 5 cm (length QU) and Base_2 = 3 cm (length RV), with the height being 4 cm. Thus,

A=12×(5+3)×4=16.A = \frac{1}{2} \times (5 + 3) \times 4 = 16.

Finally, combining the areas from the rectangle and triangle gives:

A=20x4x=16.A = 20x - 4x = 16.

We conclude that:

A=2x2+20x.A = 2x^2 + 20x.

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