16
$p = \frac{2 e}{\sqrt{f}}$
$e = 6.8$ correct to 1 decimal place - Edexcel - GCSE Maths - Question 18 - 2022 - Paper 3
Question 18
16
$p = \frac{2 e}{\sqrt{f}}$
$e = 6.8$ correct to 1 decimal place.
$f = 0.05$ correct to 1 significant figure.
Work out the upper bound for the value of $p... show full transcript
Worked Solution & Example Answer:16
$p = \frac{2 e}{\sqrt{f}}$
$e = 6.8$ correct to 1 decimal place - Edexcel - GCSE Maths - Question 18 - 2022 - Paper 3
Step 1
Calculate the Upper Bound for $e$
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Answer
Since e=6.8 correct to 1 decimal place, the upper bound can be calculated as:
Upper bound of e=6.8+0.05=6.85.
Step 2
Calculate the Upper Bound for $f$
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Answer
Since f=0.05 correct to 1 significant figure, the upper bound can be calculated as:
Upper bound of f=0.05+0.005=0.055.
Step 3
Substitute Upper Bounds into the Formula for $p$
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Answer
Substituting the upper bounds into the equation, we get: p=0.0552×6.85.
Calculating 0.055 yields approximately 0.234. Thus,
$$p \approx \frac{13.7}{0.234} \approx 58.5.$
Step 4
Final Answer
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Answer
Therefore, the upper bound for the value of p, rounded to three significant figures, is 58.5.
