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The perimeter of a right-angled triangle is 72 cm - Edexcel - GCSE Maths - Question 8 - 2018 - Paper 1

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The perimeter of a right-angled triangle is 72 cm. The lengths of its sides are in the ratio 3 : 4 : 5. Work out the area of the triangle.

Worked Solution & Example Answer:The perimeter of a right-angled triangle is 72 cm - Edexcel - GCSE Maths - Question 8 - 2018 - Paper 1

Step 1

Determine the lengths of the sides

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Answer

Let the sides of the triangle be represented as:

  • Base = 3x
  • Height = 4x
  • Hypotenuse = 5x

The perimeter of the triangle can be expressed as: extPerimeter=extBase+extHeight+extHypotenuse=3x+4x+5x=12x ext{Perimeter} = ext{Base} + ext{Height} + ext{Hypotenuse} = 3x + 4x + 5x = 12x

Setting this equal to 72 cm gives: 12x=7212x = 72

Solving for x yields: x=6x = 6

Thus, the lengths of the sides are:

  • Base = 3×6=183 \times 6 = 18 cm
  • Height = 4×6=244 \times 6 = 24 cm
  • Hypotenuse = 5×6=305 \times 6 = 30 cm

Step 2

Calculate the area of the triangle

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Answer

The area of a right-angled triangle is given by: extArea=12×Base×Height ext{Area} = \frac{1}{2} \times \text{Base} \times \text{Height} Substituting the base and height values: extArea=12×18×24 ext{Area} = \frac{1}{2} \times 18 \times 24 Calculating this gives: extArea=12×432=216 cm2 ext{Area} = \frac{1}{2} \times 432 = 216 \text{ cm}^2

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