Photo AI

The function f is given by f(x) = 2x² - 4 (a) Show that f^{-1}(50) = 3 The functions g and h are given by g(x) = x + 2 and h(x) = x² (b) Find the values of x for which hg(x) = 3x³ + x - 1 - Edexcel - GCSE Maths - Question 19 - 2019 - Paper 1

Question icon

Question 19

The-function-f-is-given-by--f(x)-=-2x²---4--(a)-Show-that-f^{-1}(50)-=-3--The-functions-g-and-h-are-given-by--g(x)-=-x-+-2-and-h(x)-=-x²--(b)-Find-the-values-of-x-for-which-hg(x)-=-3x³-+-x---1-Edexcel-GCSE Maths-Question 19-2019-Paper 1.png

The function f is given by f(x) = 2x² - 4 (a) Show that f^{-1}(50) = 3 The functions g and h are given by g(x) = x + 2 and h(x) = x² (b) Find the values of x fo... show full transcript

Worked Solution & Example Answer:The function f is given by f(x) = 2x² - 4 (a) Show that f^{-1}(50) = 3 The functions g and h are given by g(x) = x + 2 and h(x) = x² (b) Find the values of x for which hg(x) = 3x³ + x - 1 - Edexcel - GCSE Maths - Question 19 - 2019 - Paper 1

Step 1

Show that f^{-1}(50) = 3

96%

114 rated

Answer

To find the inverse of the function, we start by setting:

y=f(x)=2x24y = f(x) = 2x² - 4

Now, we can solve for x to express it in terms of y:

  1. Rearranging gives us: y+4=2x2y + 4 = 2x²

  2. Dividing both sides by 2: x2=y+42x² = \frac{y + 4}{2}

  3. Taking the square root: x=±y+42x = \pm \sqrt{\frac{y + 4}{2}}

We consider the positive root for the inverse in this context: f1(y)=y+42f^{-1}(y) = \sqrt{\frac{y + 4}{2}}

Now, substituting y = 50: f1(50)=50+42=27f^{-1}(50) = \sqrt{\frac{50 + 4}{2}} = \sqrt{27} =9=3= \sqrt{9} = 3

Thus, we verify that: f1(50)=3f^{-1}(50) = 3

Step 2

Find the values of x for which hg(x) = 3x³ + x - 1

99%

104 rated

Answer

Given:

g(x)=x+2g(x) = x + 2

So, substituting g(x) into h:

h(g(x))=h(x+2)=(x+2)2h(g(x)) = h(x + 2) = (x + 2)²

Expanding this: h(g(x))=x2+4x+4h(g(x)) = x² + 4x + 4

Now, we set up the equation:

x2+4x+4=3x3+x1x² + 4x + 4 = 3x³ + x - 1

Rearranging gives us:

3x3x+x2+4x+4+1=03x³ - x + x² + 4x + 4 + 1 = 0

Thus: 3x3+x2+3x+5=03x³ + x² + 3x + 5 = 0

To find the roots of this cubic equation, we can use numerical methods or a graphing approach. Solving this using a suitable method will yield the values of x that satisfy this equation.

Join the GCSE students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;