Photo AI

1 (a) Simplify $n^1 \times n^b$ (b) Simplify $\frac{c d^4}{c d}$ (c) Solve $\frac{5x}{2} > 7$ (Total for Question 1 is 5 marks) - Edexcel - GCSE Maths - Question 6 - 2020 - Paper 3

Question icon

Question 6

1---(a)-Simplify-$n^1-\times-n^b$---(b)-Simplify-$\frac{c-d^4}{c-d}$---(c)-Solve-$\frac{5x}{2}->-7$---(Total-for-Question-1-is-5-marks)-Edexcel-GCSE Maths-Question 6-2020-Paper 3.png

1 (a) Simplify $n^1 \times n^b$ (b) Simplify $\frac{c d^4}{c d}$ (c) Solve $\frac{5x}{2} > 7$ (Total for Question 1 is 5 marks)

Worked Solution & Example Answer:1 (a) Simplify $n^1 \times n^b$ (b) Simplify $\frac{c d^4}{c d}$ (c) Solve $\frac{5x}{2} > 7$ (Total for Question 1 is 5 marks) - Edexcel - GCSE Maths - Question 6 - 2020 - Paper 3

Step 1

Simplify $n^1 \times n^b$

96%

114 rated

Answer

To simplify the expression, we use the property of exponents that states am×an=am+na^m \times a^n = a^{m+n}. Thus, we have:

n1×nb=n1+bn^1 \times n^b = n^{1+b}

So the simplified form is n1+bn^{1+b}.

Step 2

Simplify $\frac{c d^4}{c d}$

99%

104 rated

Answer

In this case, we can simplify the expression by canceling out common factors. We see that both the numerator and the denominator have a factor of cc:

cd4cd=d4d\frac{c d^4}{c d} = \frac{d^4}{d}

Using the property of exponents again, we simplify:

d4d=d41=d3\frac{d^4}{d} = d^{4-1} = d^3

Hence, the simplified expression is d3d^3.

Step 3

Solve $\frac{5x}{2} > 7$

96%

101 rated

Answer

To solve this inequality, we first isolate xx by multiplying both sides by 2 to remove the fraction:

5x>145x > 14

Next, we divide both sides by 5:

x>145x > \frac{14}{5}

This indicates that xx must be greater than 2.82.8. Therefore, the solution is:

x>2.8x > 2.8

Join the GCSE students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;