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16 (a) On the grid, draw the graph of $x^2 + y^2 = 12.25$ (b) Hence find estimates for the solutions of the simultaneous equations $x^2 + y^2 = 12.25$ $2x + y = 1$ - Edexcel - GCSE Maths - Question 17 - 2018 - Paper 2

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Question 17

16-(a)-On-the-grid,-draw-the-graph-of-$x^2-+-y^2-=-12.25$--(b)-Hence-find-estimates-for-the-solutions-of-the-simultaneous-equations--$x^2-+-y^2-=-12.25$-$2x-+-y-=-1$-Edexcel-GCSE Maths-Question 17-2018-Paper 2.png

16 (a) On the grid, draw the graph of $x^2 + y^2 = 12.25$ (b) Hence find estimates for the solutions of the simultaneous equations $x^2 + y^2 = 12.25$ $2x + y = 1$

Worked Solution & Example Answer:16 (a) On the grid, draw the graph of $x^2 + y^2 = 12.25$ (b) Hence find estimates for the solutions of the simultaneous equations $x^2 + y^2 = 12.25$ $2x + y = 1$ - Edexcel - GCSE Maths - Question 17 - 2018 - Paper 2

Step 1

Draw the graph of $x^2 + y^2 = 12.25$

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Answer

To draw the graph of the equation x2+y2=12.25x^2 + y^2 = 12.25, we recognize that this represents a circle centered at the origin (0,0) with a radius of rac{12.25}{ ext{radius}^2} = 3.5. To plot the graph:

  1. Calculate the center and radius. We know it’s centered at the origin, and the radius is approximately 3.5.
  2. Plot points on the circle. For example, where y=0y=0, x=ext±3.5x = ext{±}3.5, and where x=0x=0, y=ext±3.5y = ext{±}3.5.
  3. Connect these points smoothly to form a circle.

Step 2

Estimate solutions for $x^2 + y^2 = 12.25$ and $2x + y = 1$

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Answer

To find estimates for the solutions of the simultaneous equations, we need to substitute values from the linear equation into the circular one. From the equation 2x+y=12x + y = 1, we can express yy as:

y=12xy = 1 - 2x.

Now we substitute this into the circle's equation:

x2+(12x)2=12.25x^2 + (1 - 2x)^2 = 12.25

Expanding this gives:

x2+(14x+4x2)=12.25x^2 + (1 - 4x + 4x^2) = 12.25

Simplifying further:

5x^2 - 4x - 11.25 = 0$$ Using the quadratic formula, we can find the x-values and then substitute back into $y = 1 - 2x$ to get corresponding y-values. The estimated intersection points can be represented as pairs on the graph.

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