16 (a) On the grid, draw the graph of $x^2 + y^2 = 12.25$
(b) Hence find estimates for the solutions of the simultaneous equations
$x^2 + y^2 = 12.25$
$2x + y = 1$ - Edexcel - GCSE Maths - Question 17 - 2018 - Paper 2
Question 17
16 (a) On the grid, draw the graph of $x^2 + y^2 = 12.25$
(b) Hence find estimates for the solutions of the simultaneous equations
$x^2 + y^2 = 12.25$
$2x + y = 1$
Worked Solution & Example Answer:16 (a) On the grid, draw the graph of $x^2 + y^2 = 12.25$
(b) Hence find estimates for the solutions of the simultaneous equations
$x^2 + y^2 = 12.25$
$2x + y = 1$ - Edexcel - GCSE Maths - Question 17 - 2018 - Paper 2
Step 1
Draw the graph of $x^2 + y^2 = 12.25$
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Answer
To draw the graph of the equation x2+y2=12.25, we recognize that this represents a circle centered at the origin (0,0) with a radius of rac{12.25}{ ext{radius}^2} = 3.5. To plot the graph:
Calculate the center and radius. We know it’s centered at the origin, and the radius is approximately 3.5.
Plot points on the circle. For example, where y=0, x=ext±3.5, and where x=0, y=ext±3.5.
Connect these points smoothly to form a circle.
Step 2
Estimate solutions for $x^2 + y^2 = 12.25$ and $2x + y = 1$
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Answer
To find estimates for the solutions of the simultaneous equations, we need to substitute values from the linear equation into the circular one. From the equation 2x+y=1, we can express y as:
y=1−2x.
Now we substitute this into the circle's equation:
x2+(1−2x)2=12.25
Expanding this gives:
x2+(1−4x+4x2)=12.25
Simplifying further:
5x^2 - 4x - 11.25 = 0$$
Using the quadratic formula, we can find the x-values and then substitute back into $y = 1 - 2x$ to get corresponding y-values. The estimated intersection points can be represented as pairs on the graph.