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Angle $ADC$ is a triangle - Edexcel - GCSE Maths - Question 7 - 2020 - Paper 1

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Angle $ADC$ is a triangle. $ED$ and $AB$ are straight lines. $EB$ is parallel to $DC$. Angle $EBC = 148^{ ext{o}}$ Angle $ADC = 63^{ ext{o}}$ Work out the size of... show full transcript

Worked Solution & Example Answer:Angle $ADC$ is a triangle - Edexcel - GCSE Maths - Question 7 - 2020 - Paper 1

Step 1

Find the size of angle EDB

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Answer

Since EDED and ABAB are straight lines, the angles on a straight line add up to 180exto180^{ ext{o}}. Therefore, extAngleEDB=180exto148exto=32exto ext{Angle } EDB = 180^{ ext{o}} - 148^{ ext{o}} = 32^{ ext{o}}

Step 2

Find the size of angle EAB

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Answer

Since EBEB is parallel to DCDC and EDED is a transversal line, we can use the alternate interior angles theorem. Thus, extAngleEAB=extAngleEDB=32exto ext{Angle } EAB = ext{Angle } EDB = 32^{ ext{o}}

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