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8 (a) Work out an estimate for the value of $ abla ext{√}63.5 imes 101.7$ (2.3)³ = 148 correct to 3 significant figures - Edexcel - GCSE Maths - Question 8 - 2019 - Paper 1

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8-(a)-Work-out-an-estimate-for-the-value-of-$-abla--ext{√}63.5--imes-101.7$--(2.3)³-=-148-correct-to-3-significant-figures-Edexcel-GCSE Maths-Question 8-2019-Paper 1.png

8 (a) Work out an estimate for the value of $ abla ext{√}63.5 imes 101.7$ (2.3)³ = 148 correct to 3 significant figures. (b) Find the value of (0.23)³ correct to... show full transcript

Worked Solution & Example Answer:8 (a) Work out an estimate for the value of $ abla ext{√}63.5 imes 101.7$ (2.3)³ = 148 correct to 3 significant figures - Edexcel - GCSE Maths - Question 8 - 2019 - Paper 1

Step 1

Work out an estimate for the value of $ abla ext{√}63.5 imes 101.7$

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Answer

To estimate the value of ext63.5imes101.7 ext{√}63.5 imes 101.7, we can round 63.5 to 64 and 101.7 to 102 for easier calculations.

First, calculate the square root:

ext64=8 ext{√}64 = 8

Now, multiply this estimate by our rounded value for 101.7:

8imes102=8168 imes 102 = 816

Thus, the estimated value is approximately 816.

Step 2

(2.3)³ = 148 correct to 3 significant figures.

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Answer

To find (2.3)3(2.3)³, calculate:

(2.3)imes(2.3)imes(2.3)=12.167(2.3) imes (2.3) imes (2.3) = 12.167

Rounding this result to 3 significant figures gives us:

12.212.2

So, (2.3)3=12.2(2.3)³ = 12.2.

Step 3

Find the value of (0.23)³ correct to 3 significant figures.

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Answer

To evaluate (0.23)3(0.23)³, we compute:

(0.23)imes(0.23)imes(0.23)=0.012167(0.23) imes (0.23) imes (0.23) = 0.012167

Rounding to 3 significant figures, we get:

0.01220.0122

Thus, (0.23)3=0.0122(0.23)³ = 0.0122.

Step 4

Find the value of $5²$

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Answer

The value of 52 is calculated as:

5imes5=255 imes 5 = 25

So, 52=255² = 25.

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