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Here are two squares, A and B - Edexcel - GCSE Maths - Question 15 - 2020 - Paper 2

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Here are two squares, A and B. The length of each side of square B is 4 cm greater than the length of each side of square A. The area of square B is 70 cm² greater ... show full transcript

Worked Solution & Example Answer:Here are two squares, A and B - Edexcel - GCSE Maths - Question 15 - 2020 - Paper 2

Step 1

The length of each side of square B is 4 cm greater than the length of each side of square A.

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Answer

Let the length of each side of square A be denoted as xx cm. Therefore, the length of each side of square B can be expressed as x+4x + 4 cm.

Step 2

The area of square B is 70 cm² greater than the area of square A.

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Answer

The area of square A is given by the formula for the area of a square, which is side length squared:

AA=x2A_A = x^2

The area of square B is:

AB=(x+4)2A_B = (x + 4)^2

According to the problem, we know that:

(x+4)2=x2+70(x + 4)^2 = x^2 + 70

Expanding the left side gives us:

x2+8x+16=x2+70x^2 + 8x + 16 = x^2 + 70

Now, simplify the equation by eliminating x2x^2 from both sides:

8x+16=708x + 16 = 70

Step 3

Solve for x.

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Answer

Subtract 16 from both sides:

8x=548x = 54

Dividing both sides by 8 gives:

x=6.75x = 6.75

Step 4

Find the area of square B.

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Answer

Now that we know the side length of square A, we can find the length of square B:

B=6.75+4=10.75extcmB = 6.75 + 4 = 10.75 ext{ cm}

Now, calculate the area of square B:

AB=(10.75)2=115.5625extcm2A_B = (10.75)^2 = 115.5625 ext{ cm}^2

Rounding to 3 significant figures gives:

AB=116extcm2A_B = 116 ext{ cm}^2

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