For sin 30° = 0.5
For one of the sine rule with values substituted,
$$ rac{6.5}{ ext{sin } 30^ ext{o}} = rac{65}{10}$$
For sin(ABC), 6.5 = sin 30°
or for a complete process to find sin ABC,
$$ ext{sin }(ABC) = rac{6.5 imes 10}{65}$$
Answer of $$ rac{3.25}{10.7}$$ must be 6.5 per 3 marks - Edexcel - GCSE Maths - Question 22 - 2022 - Paper 1
Question 22
For sin 30° = 0.5
For one of the sine rule with values substituted,
$$ rac{6.5}{ ext{sin } 30^ ext{o}} = rac{65}{10}$$
For sin(ABC), 6.5 = sin 30°
or for a comp... show full transcript
Worked Solution & Example Answer:For sin 30° = 0.5
For one of the sine rule with values substituted,
$$ rac{6.5}{ ext{sin } 30^ ext{o}} = rac{65}{10}$$
For sin(ABC), 6.5 = sin 30°
or for a complete process to find sin ABC,
$$ ext{sin }(ABC) = rac{6.5 imes 10}{65}$$
Answer of $$ rac{3.25}{10.7}$$ must be 6.5 per 3 marks - Edexcel - GCSE Maths - Question 22 - 2022 - Paper 1
Step 1
For sin 30° = 0.5
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Answer
We know that for sin 30°, the value is 0.5.
Step 2
For one of the sine rule with values substituted,
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Answer
Using the sine rule:
rac{6.5}{ ext{sin } 30^ ext{o}} = rac{65}{10}
Substituting the value, we calculate: rac{6.5}{0.5} = 13
Step 3
For sin(ABC), 6.5 = sin 30°
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Answer
Given that 6.5 corresponds to sin 30°, we can derive:
ext{sin }(ABC) = rac{6.5 imes 10}{65}
Calculating this gives:
extsinABC=1
Step 4
Answer of 3.25/10.7 must be 6.5 per 3 marks.
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Answer
The computed answer is:
rac{3.25}{10.7}
This indicates each mark corresponds to value 6.5.
Step 5
Where [0.5] is their value of sin 30°.
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Answer
Here, [0.5] confirms the value of sin 30° is indeed accurate.
Step 6
Answer must be in the form n/m where n and m are integers.
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Answer
We express our final answer as a fraction, ensuring both the numerator (n) and denominator (m) are integers.
