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Here is the graph of $y = ext{sin}^3(x)$ for $-180 \leq x \leq 180$ - Edexcel - GCSE Maths - Question 18 - 2018 - Paper 1

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Question 18

Here-is-the-graph-of-$y-=--ext{sin}^3(x)$-for-$-180-\leq-x-\leq-180$-Edexcel-GCSE Maths-Question 18-2018-Paper 1.png

Here is the graph of $y = ext{sin}^3(x)$ for $-180 \leq x \leq 180$. On the grid, sketch the graph of $y = ext{sin}^2(x) - 2$ for $-180 \leq x \leq 180$.

Worked Solution & Example Answer:Here is the graph of $y = ext{sin}^3(x)$ for $-180 \leq x \leq 180$ - Edexcel - GCSE Maths - Question 18 - 2018 - Paper 1

Step 1

Step 1: Understanding the Function

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Answer

The given function is y=extsin2(x)2y = ext{sin}^2(x) - 2. The extsin2(x) ext{sin}^2(x) function oscillates between 0 and 1. Therefore, the range of y=extsin2(x)y = ext{sin}^2(x) is [0, 1]. By subtracting 2, the range of y=extsin2(x)2y = ext{sin}^2(x) - 2 becomes [-2, -1].

Step 2

Step 2: Key Points and Intercepts

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Answer

To sketch the graph, identify key angles. For example, at x=0x = 0, y=extsin2(0)2=02=2y = ext{sin}^2(0) - 2 = 0 - 2 = -2; hence the point (0, -2) exists. Similarly, at x=90x = 90, y=extsin2(90)2=12=1y = ext{sin}^2(90) - 2 = 1 - 2 = -1, giving the point (90, -1). At x=90x = -90, the same value holds due to sine's symmetry.

Step 3

Step 3: Sketching the Graph

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Answer

The graph will be a smooth curve that oscillates between the points steered by the above evaluations, remaining in the range of [-2, -1]. It will touch the line y=2y = -2 at x=0x = 0 and reach y=1y = -1 at x=90x = 90 and x=90x = -90, with equal negative bumps around these points reflecting sinusoidal behavior.

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