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The histogram gives information about the heights, in metres, of the trees in a park - Edexcel - GCSE Maths - Question 19 - 2019 - Paper 2

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Question 19

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The histogram gives information about the heights, in metres, of the trees in a park. The histogram is incomplete. 20% of the trees in the park have a height betwee... show full transcript

Worked Solution & Example Answer:The histogram gives information about the heights, in metres, of the trees in a park - Edexcel - GCSE Maths - Question 19 - 2019 - Paper 2

Step 1

Methods to find my frequency

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Answer

To find the frequency for the interval 0-5 metres, we calculate the area of the bar:

  1. The height of the bar indicates a frequency density of 2.

  2. The width of the interval is 5 metres.

  3. Therefore, the frequency for this interval is:

    2×5=102 \times 5 = 10

Next, for the interval 5-10 metres:

  1. The height of the bar is 3.

  2. The width of the interval is also 5 metres.

  3. The frequency for this interval is:

    3×5=153 \times 5 = 15

Step 2

Methods to use areas

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Answer

For the interval 10-12.5 metres, we know that 20% of the trees fall within this range. Assuming the total number of trees is represented as T, the frequency can be calculated as:

0.2T0.2T

Now we calculate the total frequency for the intervals up to 25 metres. Since none of the trees exceed 25 metres, we can find total frequency:

  1. From the previous intervals, we have:
    • 0-5 metres: 10
    • 5-10 metres: 15
    • 10-12.5 metres: 0.2T

Total frequency = 10 + 15 + 0.2T + Frequency for 12.5-25 metres.

Step 3

Complete the histogram

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Answer

Finally, to ascertain the frequency for the interval 12.5-25 metres, we need to find:

F=T(10+15+0.2T)F = T - (10 + 15 + 0.2T)

Solving, we have:

  1. Let's calculate the total frequency again,
  2. At this point, frequency density for the final interval can be obtained by dividing this frequency by the width (12.5 metres):

For the complete histogram, ensure all bars accurately reflect these calculated frequencies.

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