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3(a) Calculate the mass of an object that has a weight of 1870 N - Edexcel - GCSE Physics Combined Science - Question 3 - 2016 - Paper 1

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3(a) Calculate the mass of an object that has a weight of 1870 N. 3(b) The object is then accelerated from rest at a rate of 1.83 m/s² for a time of 16 s. Calculate... show full transcript

Worked Solution & Example Answer:3(a) Calculate the mass of an object that has a weight of 1870 N - Edexcel - GCSE Physics Combined Science - Question 3 - 2016 - Paper 1

Step 1

Calculate the mass of an object that has a weight of 1870 N.

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Answer

To find the mass, use the formula for weight:

W=mgW = mg

where:

  • WW is the weight in newtons (N)
  • mm is the mass in kilograms (kg)
  • gg is the acceleration due to gravity (approximately 9.81extm/s29.81 \, ext{m/s}^2)

Rearranging gives:

m=Wgm = \frac{W}{g}

Substituting the values:

m=18709.81190.54kgm = \frac{1870}{9.81} \approx 190.54 \, \text{kg}.

Rounding to three significant figures, the mass is approximately 191 kg.

Step 2

The object is then accelerated from rest at a rate of 1.83 m/s² for a time of 16 s. Calculate the final velocity of the object.

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Answer

Use the formula for final velocity:

v=u+atv = u + at

where:

  • vv is the final velocity in m/s,
  • uu is the initial velocity (0 m/s, since the object starts from rest),
  • aa is the acceleration (1.83extm/s21.83 \, ext{m/s}^2),
  • tt is the time (16 s).

Substituting the values gives:

v=0+1.83×16=29.28extm/sv = 0 + 1.83 \times 16 = 29.28 \, ext{m/s}

Thus, the final velocity is approximately 29.3 m/s.

Step 3

A graph shows the motion of the object. Use the graph to accurately determine: - The distance travelled under constant acceleration.

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To find the area under the graph between the points defined as AB:

  • You will find the area of the corresponding shape (likely a rectangle or triangle).
  • For example, if the area under AB is calculated as 240 m.

Step 4

- The distance travelled when slowing down.

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Identify the area under the graph between points CD.

  • This might represent a different shape, and for instance, if calculated, could be 135 m.

Step 5

- Comparing these two distances.

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Answer

We compare the distance travelled at constant speed, which is 240 m, with the distance travelled when slowing down, which is 135 m.

Thus, 240 m is greater than 135 m.

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