Photo AI

2 (a) Which of these is a vector? A energy B force C mass D work (b) (i) State the equation that relates acceleration to change in velocity and time taken - Edexcel - GCSE Physics Combined Science - Question 2 - 2020 - Paper 1

Question icon

Question 2

2-(a)-Which-of-these-is-a-vector?--A-energy-B-force-C-mass-D-work--(b)-(i)-State-the-equation-that-relates-acceleration-to-change-in-velocity-and-time-taken-Edexcel-GCSE Physics Combined Science-Question 2-2020-Paper 1.png

2 (a) Which of these is a vector? A energy B force C mass D work (b) (i) State the equation that relates acceleration to change in velocity and time taken. (ii) A... show full transcript

Worked Solution & Example Answer:2 (a) Which of these is a vector? A energy B force C mass D work (b) (i) State the equation that relates acceleration to change in velocity and time taken - Edexcel - GCSE Physics Combined Science - Question 2 - 2020 - Paper 1

Step 1

Which of these is a vector?

96%

114 rated

Answer

The correct answer is B: force. A vector is a quantity that has both magnitude and direction, and force fits this definition.

Step 2

State the equation that relates acceleration to change in velocity and time taken.

99%

104 rated

Answer

The equation for acceleration (a) is given by:

a=Δvta = \frac{\Delta v}{t}

where (\Delta v) is the change in velocity and (t) is the time taken.

Step 3

Calculate the acceleration of the van.

96%

101 rated

Answer

To calculate the acceleration of the van, we can apply the equation:

  1. Determine the change in velocity:

    • Initial velocity (u) = 2 m/s
    • Final velocity (v) = 20 m/s
    • Change in velocity ((\Delta v)) = v - u = 20 m/s - 2 m/s = 18 m/s
  2. Time taken (t) = 12 s

  3. Substitute into the acceleration formula: a=Δvt=18 m/s12 s=1.5 m/s2a = \frac{\Delta v}{t} = \frac{18 \text{ m/s}}{12 \text{ s}} = 1.5 \text{ m/s}^2

Thus, the acceleration of the van is 1.5 m/s².

Join the GCSE students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;