Figure 6 shows a graph of current against potential difference for an electrical component - Edexcel - GCSE Physics Combined Science - Question 4 - 2018 - Paper 1
Question 4
Figure 6 shows a graph of current against potential difference for an electrical component.
Which electrical component will show this variation of current with pote... show full transcript
Worked Solution & Example Answer:Figure 6 shows a graph of current against potential difference for an electrical component - Edexcel - GCSE Physics Combined Science - Question 4 - 2018 - Paper 1
Step 1
Which electrical component will show this variation of current with potential difference?
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Answer
The component that shows this non-linear variation of current with potential difference, where the curve indicates that current increases with voltage until a certain point, is a D diode. This is because other options either have a linear relationship (like resistors) or behave differently (like thermistors).
Step 2
(i) Calculate the power of the lamp.
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Answer
To find the power of the lamp, we use the formula:
P=IimesV
Substituting in the values:
P=0.12imes0.24
Calculating this gives:
P=0.0288extW
Thus, the power of the lamp is approximately 0.029 W when rounded.
