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Figure 10 shows two electrical devices for heating water - Edexcel - GCSE Physics Combined Science - Question 6 - 2019 - Paper 1

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Figure 10 shows two electrical devices for heating water. The current in the element of the immersion heater is 14 A. The power of the immersion heater is 130 W. ... show full transcript

Worked Solution & Example Answer:Figure 10 shows two electrical devices for heating water - Edexcel - GCSE Physics Combined Science - Question 6 - 2019 - Paper 1

Step 1

Calculate the resistance of the immersion heater.

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Answer

To determine the resistance (R) of the immersion heater, we can use the formula relating power (P), current (I), and resistance:

P=I2RP = I^2 R

Given that:

  • Power, P=130WP = 130 \, W
  • Current, I=14AI = 14 \, A

Rearranging the formula for resistance, we have:

R=PI2R = \frac{P}{I^2}

Substituting the values:

R=130142R = \frac{130}{14^2}

Calculating:

R=1301960.663ΩR = \frac{130}{196} \approx 0.663 \Omega

Rounding to two significant figures, the resistance of the immersion heater is:

R=0.66ΩR = 0.66 \Omega

Step 2

State two differences between the movement of charge in the heating element of the kettle and the movement of charge in the immersion heater.

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Answer

  1. The rate of charge flow in the immersion heater is greater than in the kettle; specifically, the immersion heater has a current of 14 A, which corresponds to a higher flow of charge compared to 8.3 A in the kettle.

  2. The direction of the flow of charge in the heating element of the kettle changes continuously due to alternating current, whereas in the immersion heater it flows in one direction (direct current).

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