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Figure 2 shows an energy transfer diagram for a steam engine - Edexcel - GCSE Physics Combined Science - Question 2 - 2019 - Paper 1

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Figure 2 shows an energy transfer diagram for a steam engine. The diagram shows the amounts of energy transferred each second by the steam engine. energy input 2000... show full transcript

Worked Solution & Example Answer:Figure 2 shows an energy transfer diagram for a steam engine - Edexcel - GCSE Physics Combined Science - Question 2 - 2019 - Paper 1

Step 1

Calculate the amount of wasted energy.

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Answer

To find the amount of wasted energy, subtract the useful energy output from the total energy input:

wastedenergy=totalenergyinputusefulenergyoutput=2000J160J=1840J.wasted \, energy = total \, energy \, input - useful \, energy \, output = 2000 \, J - 160 \, J = 1840 \, J.

Step 2

Calculate the efficiency of the steam engine.

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Answer

Using the efficiency formula, we substitute the values:

efficiency=usefulenergytotalenergy=160J2000J=0.08.efficiency = \frac{useful \, energy}{total \, energy} = \frac{160 \, J}{2000 \, J} = 0.08.

To express efficiency as a percentage, multiply by 100:

efficiency=0.08×100=8%.efficiency = 0.08 \times 100 = 8\%.

Step 3

State what happens to the wasted energy.

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Answer

The wasted energy is generally lost to the environment as heat, which may contribute to energy inefficiency and can cause thermal pollution.

Step 4

State two ways that the use of coal might be harmful to the environment.

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Answer

  1. Burning coal releases carbon dioxide, a greenhouse gas that contributes to climate change.
  2. Coal burning can produce harmful pollutants like sulfur dioxide, leading to acid rain.

Step 5

Calculate the kinetic energy of the model train.

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Answer

Using the kinetic energy formula:

kineticenergy=12×mass×(speed)2=12×8.0kg×(1.5m/s)2.kinetic \, energy = \frac{1}{2} \times mass \times (speed)^{2} = \frac{1}{2} \times 8.0 \, kg \times (1.5 \, m/s)^{2}.

Calculating this gives:

kineticenergy=12×8.0×2.25=9.0J.kinetic \, energy = \frac{1}{2} \times 8.0 \times 2.25 = 9.0 \, J.

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