This question is about using the mains electricity supply - Edexcel - GCSE Physics Combined Science - Question 3 - 2021 - Paper 1

The energy transferred can be calculated using the equation:

$E = V \times I \times t$

where:

• $V = 230 \text{ V}$
• $I = 7.4 \text{ A}$
• $t = 120 \text{ s}$.

Thus,

$E = 230 \times 7.4 \times 120 = 204240 \text{ J}$

Wire X is the earth wire and Wire Y is the live wire.

Component Z is the fuse.

To find the input current, we will rearrange the equation:

$I_p \times 230 = 2.37 \times 190$

Solving for $I_p$ gives:

$I_p = \frac{(2.37 \times 190)}{230} \approx 0.196 \text{ A}$