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1. (a) Which of these is the equation for work done? A work done = force ÷ distance moved in direction of force B work done = force × distance moved in direction of force C work done = force × distance moved at right angles to direction of force D work done = force × distance moved at right angles to direction of force (b) A ball has a mass of 0.046 kg - Edexcel - GCSE Physics Combined Science - Question 1 - 2019 - Paper 1

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1.-(a)-Which-of-these-is-the-equation-for-work-done?----A-work-done-=-force-÷-distance-moved-in-direction-of-force----B-work-done-=-force-×-distance-moved-in-direction-of-force----C-work-done-=-force-×-distance-moved-at-right-angles-to-direction-of-force----D-work-done-=-force-×-distance-moved-at-right-angles-to-direction-of-force--(b)-A-ball-has-a-mass-of-0.046-kg-Edexcel-GCSE Physics Combined Science-Question 1-2019-Paper 1.png

1. (a) Which of these is the equation for work done? A work done = force ÷ distance moved in direction of force B work done = force × distance moved in directi... show full transcript

Worked Solution & Example Answer:1. (a) Which of these is the equation for work done? A work done = force ÷ distance moved in direction of force B work done = force × distance moved in direction of force C work done = force × distance moved at right angles to direction of force D work done = force × distance moved at right angles to direction of force (b) A ball has a mass of 0.046 kg - Edexcel - GCSE Physics Combined Science - Question 1 - 2019 - Paper 1

Step 1

Which of these is the equation for work done?

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Answer

The correct equation for work done is:

B work done = force × distance moved in direction of force.

Step 2

Calculate the change in gravitational potential energy when the ball is lifted through a vertical height of 2.05 m.

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Answer

To calculate the change in gravitational potential energy (ΔGPE), we use the equation:

ΔGPE=m×g×hΔGPE = m × g × h

Where:

  • m = 0.046 kg (mass of the ball)
  • g = 9.81 m/s² (acceleration due to gravity)
  • h = 2.05 m (height)

Now substituting the values:

ΔGPE=0.046imes9.81imes2.05 ΔGPE0.93extJΔGPE = 0.046 imes 9.81 imes 2.05\ ΔGPE ≈ 0.93 ext{ J}

Step 3

Calculate the kinetic energy of the ball when the speed of the ball is 3.5 m/s.

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Answer

The kinetic energy (KE) of an object can be calculated using the formula:

KE=12mv2KE = \frac{1}{2} m v^2

Where:

  • m = 0.046 kg (mass of the ball)
  • v = 3.5 m/s (velocity of the ball)

Substituting the values:

KE=12×0.046×(3.5)2 KE=0.28extJKE = \frac{1}{2} × 0.046 × (3.5)^2\ KE = 0.28 ext{ J}

Step 4

Explain what happens to the energy of the ball when it is released.

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Answer

When the ball is released, it converts gravitational potential energy into kinetic energy as it falls. However, as it moves, some of this energy is dissipated due to air resistance, sound, and heat due to friction. Thus, not all of the potential energy is converted into kinetic energy, indicating that the system is not 100% efficient.

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