Photo AI

5 (a) Which of these describes isotopes of an element? A same atomic number different number of neutrons B same atomic number different number of protons C same mass number different number of neutrons D same mass number different number of protons (b) Figure 7 represents a decay that can happen inside the nucleus of an atom - Edexcel - GCSE Physics Combined Science - Question 5 - 2020 - Paper 1

Question icon

Question 5

5-(a)-Which-of-these-describes-isotopes-of-an-element?--A--same-atomic-number--different-number-of-neutrons-B--same-atomic-number--different-number-of-protons-C--same-mass-number--different-number-of-neutrons-D--same-mass-number--different-number-of-protons--(b)-Figure-7-represents-a-decay-that-can-happen-inside-the-nucleus-of-an-atom-Edexcel-GCSE Physics Combined Science-Question 5-2020-Paper 1.png

5 (a) Which of these describes isotopes of an element? A same atomic number different number of neutrons B same atomic number different number of protons C sam... show full transcript

Worked Solution & Example Answer:5 (a) Which of these describes isotopes of an element? A same atomic number different number of neutrons B same atomic number different number of protons C same mass number different number of neutrons D same mass number different number of protons (b) Figure 7 represents a decay that can happen inside the nucleus of an atom - Edexcel - GCSE Physics Combined Science - Question 5 - 2020 - Paper 1

Step 1

Which of these describes isotopes of an element?

96%

114 rated

Answer

Isotopes are variants of the same element that differ in the number of neutrons while having the same atomic number. Thus, the correct answer is:

A: same atomic number, different number of neutrons.

Step 2

Which decay is represented in Figure 7?

99%

104 rated

Answer

Figure 7 depicts a process where a neutron is produced alongside a proton, a characteristic of beta minus decay. In this process, a neutron in the nucleus converts into a proton and emits a beta particle (electron) and an antineutrino.

Step 3

Estimate the activity of this source in the year 2020.

96%

101 rated

Answer

The half-life of cobalt-60 is 5 years, which means after 5 years, the activity will reduce to half.

Starting with an initial activity of 38.5 kBq in the year 2000, we calculate:

  • After 5 years (2005):

    extActivity2005=38.5extkBq2=19.25extkBq ext{Activity}_{2005} = \frac{38.5 ext{ kBq}}{2} = 19.25 ext{ kBq}

  • After 10 years (2010):

    extActivity2010=19.25extkBq2=9.625extkBq ext{Activity}_{2010} = \frac{19.25 ext{ kBq}}{2} = 9.625 ext{ kBq}

  • After 15 years (2015):

    extActivity2015=9.625extkBq2=4.8125extkBq ext{Activity}_{2015} = \frac{9.625 ext{ kBq}}{2} = 4.8125 ext{ kBq}

  • After 20 years (2020):

    extActivity2020=4.8125extkBq2=2.40625extkBq ext{Activity}_{2020} = \frac{4.8125 ext{ kBq}}{2} = 2.40625 ext{ kBq}

Thus, the estimated activity of the cobalt-60 source in the year 2020 is approximately 2.41 kBq.

Join the GCSE students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;