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Figure 10 shows a football kicked against a wall - Edexcel - GCSE Physics Combined Science - Question 6 - 2023 - Paper 1

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Figure 10 shows a football kicked against a wall. The football has a mass of 0.42 kg. (i) The football gains 11 J of gravitational potential energy as it moves fro... show full transcript

Worked Solution & Example Answer:Figure 10 shows a football kicked against a wall - Edexcel - GCSE Physics Combined Science - Question 6 - 2023 - Paper 1

Step 1

Calculate the height at which the ball hits the wall.

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Answer

To find the height, we use the equation for change in gravitational potential energy (ΔGPE):

ΔGPE=m×g×ΔhΔGPE = m × g × Δh

Rearranging this gives:

Δh=ΔGPEm×gΔh = \frac{ΔGPE}{m × g}

We know:

  • ΔGPE = 11 J
  • m = 0.42 kg
  • g = 10 N/kg

Substituting these values into the equation:

Δh=11J0.42kg×10N/kg=114.2≈2.62mΔh = \frac{11 J}{0.42 kg × 10 N/kg} = \frac{11}{4.2} ≈ 2.62 m

Thus, the height at which the ball hits the wall is approximately 2.62 m.

Step 2

Calculate the kinetic energy of the football when it is moving at a velocity of 12 m/s.

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Answer

To calculate the kinetic energy (KE), we use the formula:

KE=12mv2KE = \frac{1}{2} m v^2

Where:

  • m = 0.42 kg
  • v = 12 m/s

Substituting the values:

KE=12×0.42kg×(12m/s)2KE = \frac{1}{2} × 0.42 kg × (12 m/s)^2

Calculating:

KE=12×0.42kg×144m2/s2=30.24JKE = \frac{1}{2} × 0.42 kg × 144 m^2/s^2 = 30.24 J

Thus, the kinetic energy of the football is 30.24 J.

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