Figure 4 shows a football kicked against a wall - Edexcel - GCSE Physics Combined Science - Question 2 - 2023 - Paper 1

From the problem, we have:

• Gravitational potential energy gained, ΔGPE = 11 J
• Mass of the football, m = 0.42 kg
• Gravitational field strength, g = 10 N/kg

We can rearrange the equation to solve for height (Δh):

$$Δh = \frac{ΔGPE}{m \times g}$$

Substituting the known values into the equation, we get:

$$Δh = \frac{11}{0.42 \times 10}$$

Now, calculating:

1. Calculate the denominator:

   • 0.42 × 10 = 4.2

2. Now calculate Δh:

   • $Δh = \frac{11}{4.2} \approx 2.619$

Thus, rounding to an appropriate number of significant figures, the height at which the ball hits the wall is approximately 2.6 m.