6 (a) An atom of mass 6.6 × 10^{-27} kg is moving with a velocity of 480 m/s - Edexcel - GCSE Physics Combined Science - Question 6 - 2023 - Paper 1

To calculate the force (F) exerted by the wall on the ball, we can use the formula:

$F = \frac{\Delta p}{\Delta t}$

where:

• $\Delta p$ is the change in momentum, and
• $\Delta t$ is the time of contact.

First, we calculate the change in momentum: $\Delta p = p_{final} - p_{initial} = (0.60 ext{ kg m/s}) - (0.80 ext{ kg m/s}) = -0.20 ext{ kg m/s}$

Next, we use the time of contact, which is given as 70 ms (or $70 imes 10^{-3}$ seconds):

Now substituting in the values: $F = \frac{-0.20 ext{ kg m/s}}{70 \times 10^{-3} ext{ s}}$

Calculating this gives: $F = -2.857 ext{ N}$ (The negative sign indicates the force is in the opposite direction of the initial momentum of the ball.)