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Figure 6 shows a graph of current against potential difference for an electrical component - Edexcel - GCSE Physics Combined Science - Question 4 - 2018 - Paper 1

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Figure 6 shows a graph of current against potential difference for an electrical component. Which electrical component will show this variation of current with pote... show full transcript

Worked Solution & Example Answer:Figure 6 shows a graph of current against potential difference for an electrical component - Edexcel - GCSE Physics Combined Science - Question 4 - 2018 - Paper 1

Step 1

Which electrical component will show this variation of current with potential difference?

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Answer

The component that shows a variation of current with potential difference as described in the question is a diode. This is evidenced by the graph indicating that the current increases only after a certain threshold potential difference, which is characteristic behavior of a diode.

Step 2

Calculate the power of the lamp.

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Answer

To calculate the power of the lamp, we will use the formula:

P=IimesVP = I imes V

Substituting the given values:

  • Current, I=0.12 AI = 0.12 \, \text{A}
  • Potential difference, V=0.24 VV = 0.24 \, \text{V}

Thus, the calculation becomes:

P=0.12 A×0.24 V=0.0288 WP = 0.12 \, \text{A} \times 0.24 \, \text{V} = 0.0288 \, \text{W}

Therefore, the power of the lamp is approximately 0.029 W.

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