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A resistor is connected to a power supply - Edexcel - GCSE Physics Combined Science - Question 5 - 2018 - Paper 1

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A resistor is connected to a power supply. The potential difference across the resistor is 6.0V. (i) Which of these corresponds to a potential difference of 6.0V? ... show full transcript

Worked Solution & Example Answer:A resistor is connected to a power supply - Edexcel - GCSE Physics Combined Science - Question 5 - 2018 - Paper 1

Step 1

(i) Which of these corresponds to a potential difference of 6.0V?

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Answer

The correct answer is option C: 6.0 joules per coulomb. This is because potential difference (voltage) is defined as energy per unit charge, thus 6.0 joules per coulomb reflects a potential difference of 6.0V.

Step 2

(ii) Calculate, in minutes, the time taken for this amount of charge to flow through the resistor.

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Answer

To calculate time, we can use the formula:

Q=IimestQ = I imes t

Where:

  • QQ is the charge (42 C)
  • II is the current (200 mA = 0.2 A)
  • tt is time in seconds.

Rearranging the formula gives us:

t=QI=420.2=210secondst = \frac{Q}{I} = \frac{42}{0.2} = 210 \, \text{seconds}

To convert seconds to minutes:

t=210603.5minutest = \frac{210}{60} \approx 3.5 \, \text{minutes}

Step 3

(iii) Calculate the total energy transferred by the 6.0V power supply.

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Answer

The energy transferred can be calculated using the formula:

E=V×QE = V \times Q

Where:

  • EE is the energy transferred (in joules)
  • VV is the potential difference (6.0 V)
  • QQ is the charge (42 C)

Thus, substituting in the values:

E=6.0×42=252JE = 6.0 \times 42 = 252 \, \text{J}

Step 4

(b) Explain why the resistor becomes warm.

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Answer

The resistor becomes warm due to collisions between the flowing electrons and the atoms in the lattice structure of the resistor material. As the electrons move through the resistor, they collide with the fixed lattice ions, transferring energy to them. This results in an increase in the vibrational energy of the lattice, which is perceived as a rise in temperature.

Step 5

(c) Deduce how the resistors have been arranged inside the cardboard tube.

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Answer

Since there are two 100 ohm resistors, if they were arranged in series, the equivalent resistance would be:

Rtotal=R1+R2=100Ω+100Ω=200ΩR_{total} = R_1 + R_2 = 100 \, \Omega + 100 \, \Omega = 200 \, \Omega

Given that the current (I) is 1.2 A and the total voltage (V) is 6.0 V, the required equivalent resistance would be:

R=VI=6.01.2=5ΩR = \frac{V}{I} = \frac{6.0}{1.2} = 5 \, \Omega

Since this value (5 ohms) is less than the 200 ohm total resistance, it means the resistors must be connected in parallel, which would allow current to be shared and result in a lower total resistance.

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