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A cyclist is riding a bicycle at a steady velocity of 12 m/s - Edexcel - GCSE Physics Combined Science - Question 6 - 2018 - Paper 1

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A cyclist is riding a bicycle at a steady velocity of 12 m/s. The cyclist and bicycle have a total mass of 68 kg. (a) Calculate the kinetic energy of the cyclist an... show full transcript

Worked Solution & Example Answer:A cyclist is riding a bicycle at a steady velocity of 12 m/s - Edexcel - GCSE Physics Combined Science - Question 6 - 2018 - Paper 1

Step 1

Calculate the kinetic energy of the cyclist and bicycle.

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Answer

To find the kinetic energy (KE), we use the formula:

KE=12mv2KE = \frac{1}{2} m v^2

where: m = total mass = 68 kg, v = velocity = 12 m/s.

Substituting the values into the equation:

KE=12×68×(12)2=12×68×144=4896J.KE = \frac{1}{2} \times 68 \times (12)^2 = \frac{1}{2} \times 68 \times 144 = 4896 J.

Hence, the kinetic energy of the cyclist and bicycle is approximately 4900 J.

Step 2

Describe the energy transfers that happen when the cyclist uses the brakes to stop.

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Answer

When the cyclist uses the brakes, the kinetic energy of the cyclist and bicycle is reduced, which means the motion energy is transferred.

This energy is usually converted into heat energy due to friction between the brake pads and the wheels, causing the bicycle to decelerate. In summary, kinetic energy is transformed into thermal energy, leading to a stop.

Step 3

Calculate the average force the cyclist exerts.

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Answer

To find the average force exerted by the cyclist, we can use the work-energy principle:

Work=Force×Distance.Work = Force \times Distance.

Given that the work done is 1600 J and the distance traveled is 28 m, we can rearrange the formula to solve for force:

Force=WorkDistance=16002857.14N.Force = \frac{Work}{Distance} = \frac{1600}{28} \approx 57.14 N.

Therefore, the average force the cyclist exerts is approximately 57 N.

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