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Figure 10 shows a small steel ball held at a height, h, above the ground - Edexcel - GCSE Physics - Question 7 - 2021 - Paper 1

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Figure 10 shows a small steel ball held at a height, h, above the ground. The ball is released and allowed to fall to the ground. The height h is 1.4 m. Calculate... show full transcript

Worked Solution & Example Answer:Figure 10 shows a small steel ball held at a height, h, above the ground - Edexcel - GCSE Physics - Question 7 - 2021 - Paper 1

Step 1

Calculate the time, t for the ball to reach the ground.

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Answer

To find the time it takes for the ball to reach the ground, we can use the formula:

t2=2hgt^2 = \frac{2h}{g}

Substituting the values:

  • Height, h = 1.4 m
  • Acceleration due to gravity, g = 10 m/s²

Thus, t2=2×1.410t^2 = \frac{2 \times 1.4}{10}

Calculating this: t2=2.810=0.28t^2 = \frac{2.8}{10} = 0.28

To find t, take the square root: t=0.280.53st = \sqrt{0.28} \approx 0.53 \, \text{s}

Step 2

Suggest one reason why the students’ value for t is different from the calculated value.

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Answer

One possible reason for the different average value of t recorded by the students compared to the calculated value is that the students’ reaction times when using the stopwatch could have caused a delay in starting or stopping the timer.

Step 3

Suggest one improvement the students could make to their procedure so that their value for t is closer to the calculated value.

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Answer

One improvement could be to use electronic timing gates to measure the fall time accurately, thus minimizing human reaction time errors.

Step 4

Calculate the magnitude of the force exerted by the floor on the box.

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Answer

To find the force exerted by the floor on the box, we can use the formula for momentum change:

force=change in momentumtime\text{force} = \frac{\text{change in momentum}}{\text{time}}

The momentum just before it hits the floor is 8.7 kg m/s and it takes 0.35 s to come to rest:

Thus, force=8.70.3524.857 N25 N\text{force} = \frac{8.7}{0.35} \approx 24.857 \text{ N} \approx 25 \text{ N}

Step 5

State the magnitude and direction of the force exerted by the box on the floor.

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Answer

The magnitude of the force exerted by the box on the floor is 25 N, and the direction is upwards, opposing the force of gravity.

Step 6

Calculate the mass of the ball.

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Answer

To find the mass of the ball, we can use the momentum formula:

momentum=mv\text{momentum} = m \cdot v

Where momentum at point S is 0.40 kg m/s. First, we need to calculate the velocity (v) using:

v2=u2+2asv^2 = u^2 + 2as

Where:

  • Initial velocity, u = 0 (the ball starts from rest)
  • Acceleration, a = 10 m/s²
  • Distance dropped, s = 3.8 m

Substituting the values:

= 76$$ Thus, v = \sqrt{76} \approx 8.7 \, \text{m/s}. Now substituting back to find mass: $$0.40 = m \cdot 8.7 \ \Rightarrow m = \frac{0.40}{8.7} \approx 0.046 \, \text{kg}$$

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