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The students took five results for the left hand and five results for the right hand - Edexcel - GCSE Physics - Question 6 - 2016 - Paper 1

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The students took five results for the left hand and five results for the right hand. Figure 5 shows their results. which hand rials 1 trials 2 trials 3 trials 4 tr... show full transcript

Worked Solution & Example Answer:The students took five results for the left hand and five results for the right hand - Edexcel - GCSE Physics - Question 6 - 2016 - Paper 1

Step 1

Calculate the average distance dropped for the right hand.

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Answer

To find the average distance dropped for the right hand, we need to sum all the distances dropped in each trial and divide by the number of trials.

The distances dropped are as follows:

  • Trial 1: 17.5 cm
  • Trial 2: 16.1 cm
  • Trial 3: 19.4 cm
  • Trial 4: 18.6 cm
  • Trial 5: 20.2 cm

Calculating the total distance dropped:

extTotal=17.5+16.1+19.4+18.6+20.2=91.8extcm ext{Total} = 17.5 + 16.1 + 19.4 + 18.6 + 20.2 = 91.8 ext{ cm}

Now, divide the total by the number of trials (5):

extAverage=91.85=18.36extcm ext{Average} = \frac{91.8}{5} = 18.36 ext{ cm}

To give the answer to 2 significant figures, we round 18.36 to 18 cm.

Step 2

Calculate the average time for the left hand.

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Answer

To calculate the average time for the left hand, we can use the relationship defined by the equation:

exttime2=extdistance ext{time}^2 = ext{distance}

We will use the average distance dropped for the left hand. According to Figure 5, the average for the left hand is 14 cm. Plugging this value into the equation:

exttime2=14extcm ext{time}^2 = 14 ext{ cm}

Now, taking the square root to solve for time:

exttime=extsqrt(14)exts3.74exts ext{time} = ext{sqrt}(14) ext{ s} ≈ 3.74 ext{ s}

Thus, the average time for the left hand is approximately 3.74 s.

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