A football is kicked against a wall as shown in Figure 5 - Edexcel - GCSE Physics - Question 3 - 2023 - Paper 1

To find the height (Δh), we use the formula for gravitational potential energy:

$$ΔGPE = m × g × Δh$$

Given:

• ΔGPE = 11 J
• m = 0.42 kg
• g = 10 N/kg

We can rearrange the formula to solve for Δh:

$$Δh = \frac{ΔGPE}{m × g}$$

Substituting the values:

$$Δh = \frac{11}{0.42 × 10} = \frac{11}{4.2} ≈ 2.618 m$$

Rounding this value to one decimal place, we get:

$$Δh ≈ 2.6 m$$

Thus, the height at which the ball hits the wall is approximately 2.6 m.