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(a) Which ray diagram shows total reflection at an air and glass boundary? (b) Figure 1 is a ray diagram for a converging lens used as a magnifying glass - Edexcel - GCSE Physics - Question 1 - 2022 - Paper 1

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(a)-Which-ray-diagram-shows-total-reflection-at-an-air-and-glass-boundary?--(b)-Figure-1-is-a-ray-diagram-for-a-converging-lens-used-as-a-magnifying-glass-Edexcel-GCSE Physics-Question 1-2022-Paper 1.png

(a) Which ray diagram shows total reflection at an air and glass boundary? (b) Figure 1 is a ray diagram for a converging lens used as a magnifying glass. (i) Usin... show full transcript

Worked Solution & Example Answer:(a) Which ray diagram shows total reflection at an air and glass boundary? (b) Figure 1 is a ray diagram for a converging lens used as a magnifying glass - Edexcel - GCSE Physics - Question 1 - 2022 - Paper 1

Step 1

Using information from Figure 1, determine the magnification of the virtual image.

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Answer

To calculate the magnification of the virtual image using the provided equation, we can use the heights from the ray diagram in Figure 1. Assuming the height of the virtual image is twice that of the object, it can be expressed as:

magnification=height of imageheight of object=2hh=2\text{magnification} = \frac{\text{height of image}}{\text{height of object}} = \frac{2h}{h} = 2

Therefore, the magnification of the virtual image is 2.

Step 2

Describe one way the magnification of the image could be increased.

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Answer

One way to increase the magnification of the image is to use a lens with a greater curvature or a higher power. A stronger lens will have a shorter focal length, magnifying the image more effectively. Alternatively, moving the lens closer to the object will also increase the magnification, as it alters the distance between the object and the lens.

Step 3

Calculate the focal length, f, of the lens.

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Answer

To find the focal length, we use the lens formula:

1f=1a+1b\frac{1}{f} = \frac{1}{a} + \frac{1}{b}

Here, we know:

  • a = 20 cm
  • b = 40 cm

Plugging in the values:

1f=120+140=240+140=340\frac{1}{f} = \frac{1}{20} + \frac{1}{40} = \frac{2}{40} + \frac{1}{40} = \frac{3}{40}

To find f, we take the reciprocal:

f=40313.33 cm\therefore f = \frac{40}{3} \approx 13.33 \text{ cm}

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