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Figure 6 shows two objects, E and D - Edexcel - GCSE Physics - Question 4 - 2023 - Paper 1

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Figure 6 shows two objects, E and D. E emits a sound. D detects the sound. E is moving in the direction shown by the arrow, but D is not moving. E emits a sound of ... show full transcript

Worked Solution & Example Answer:Figure 6 shows two objects, E and D - Edexcel - GCSE Physics - Question 4 - 2023 - Paper 1

Step 1

Calculate the difference between the wavelengths

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Answer

To find the difference between the wavelength emitted by E and the wavelength detected by D, we subtract the two values:

extDifference=extWavelengthdetectedextWavelengthemitted ext{Difference} = ext{Wavelength detected} - ext{Wavelength emitted} =1.98extm1.86extm= 1.98 ext{ m} - 1.86 ext{ m}

This calculations gives: =0.12extm= 0.12 ext{ m}

Therefore, the difference in wavelength is 0.12 m.

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