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Figure 3 shows the parts in an electrical circuit - Edexcel - GCSE Physics - Question 2 - 2023 - Paper 2

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Figure 3 shows the parts in an electrical circuit. The battery symbol and some of the connecting wires have been drawn for you. (c) (i) There is a current of 0.4... show full transcript

Worked Solution & Example Answer:Figure 3 shows the parts in an electrical circuit - Edexcel - GCSE Physics - Question 2 - 2023 - Paper 2

Step 1

Calculate the total charge that flows through the lamp in 30 seconds.

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Answer

To calculate the total charge, we use the equation:

charge=current×timecharge = current \times time

Given:

  • current = 0.46 A
  • time = 30 s

Substituting the values:

charge=0.46 A×30 s=13.8 Ccharge = 0.46 \text{ A} \times 30 \text{ s} = 13.8 \text{ C}

Therefore, the charge that flows through the lamp is 13.8 C.

Step 2

Calculate the energy transferred to the lamp in one minute.

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Answer

To calculate the energy transferred, we use the equation:

energy transferred=current×voltage×timeenergy \ transferred = current \times voltage \times time

Given:

  • current = 0.46 A
  • voltage = 6.0 V
  • time = 1 minute = 60 seconds

Substituting the values:

energy transferred=0.46 A×6.0 V×60 senergy \ transferred = 0.46 \text{ A} \times 6.0 \text{ V} \times 60 \text{ s}

Calculating:

energy transferred=0.46×6.0×60=165.6 Jenergy \ transferred = 0.46 \times 6.0 \times 60 = 165.6 \text{ J}

Thus, the energy transferred to the lamp is approximately 166 J.

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