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A student investigates the resistance of a lamp - Edexcel - GCSE Physics - Question 5 - 2016 - Paper 1

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A student investigates the resistance of a lamp. She obtains these readings for the potential difference (voltage) across the lamp and the current in the lamp. | vo... show full transcript

Worked Solution & Example Answer:A student investigates the resistance of a lamp - Edexcel - GCSE Physics - Question 5 - 2016 - Paper 1

Step 1

Calculate the resistance, R, of the lamp.

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Answer

To calculate the resistance, we use the formula:

R=VIR = \frac{V}{I}

Substituting the known values:

R=6.00.40R = \frac{6.0}{0.40}

Now, evaluating this gives:

R=15  ΩR = 15 \; \Omega

Step 2

Calculate the power supplied to the lamp.

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Answer

Power can be calculated using the formula:

P=V×IP = V \times I

By substituting the given values:

P=6.0×0.40P = 6.0 \times 0.40

Evaluating this gives:

P=2.4  WP = 2.4 \; W

Step 3

Calculate the amount of energy transferred by the lamp in 40 s.

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Answer

The energy transferred can be calculated using:

E=P×tE = P \times t

Substituting the known values:

E=2.4×40E = 2.4 \times 40

Evaluating this gives:

E=96  JE = 96 \; J

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