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A man monitors how much money he spends on electricity - Edexcel - GCSE Physics - Question 6 - 2015 - Paper 1

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A man monitors how much money he spends on electricity. He uses a device which calculates the cost of electrical energy used. He connects his 2.9 kW electric kettle ... show full transcript

Worked Solution & Example Answer:A man monitors how much money he spends on electricity - Edexcel - GCSE Physics - Question 6 - 2015 - Paper 1

Step 1

Calculate the current in the kettle element.

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Answer

To calculate the current, we use the formula: I=PVI = \frac{P}{V} where:

  • II = Current (in Amperes)
  • PP = Power (in Watts)
  • VV = Voltage (in Volts)

Substituting the known values: I=2900 W230 VI = \frac{2900 \text{ W}}{230 \text{ V}} Calculating further gives: I=12.61 AI = 12.61 \text{ A}

Step 2

Calculate the length of time for which the kettle has been switched on during the week.

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Answer

First, we need to find out how much electrical energy the kettle used in kWh: The total cost is 97 p. The cost of 1 kWh is 17 p. To find the total energy used in kWh, we divide: Total energy (kWh)=97 p17 p/kWh=5.71 kWh\text{Total energy (kWh)} = \frac{97 \text{ p}}{17 \text{ p/kWh}} = 5.71 \text{ kWh}

Next, using the power of the kettle (2.9 kW), we can calculate the time: Time (hours)=Energy (kWh)Power (kW)=5.71 kWh2.9 kW=1.97 hours\text{Time (hours)} = \frac{\text{Energy (kWh)}}{\text{Power (kW)}} = \frac{5.71 \text{ kWh}}{2.9 \text{ kW}} = 1.97 \text{ hours} Therefore, the kettle has been switched on for approximately 1.97 hours during the week.

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