A student investigates the resistance of a lamp. She obtains these readings for the potential difference (voltage) across the lamp and the current in the lamp. | voltage in V | current in A | |--------------|---------------| | 6.0 | 0.40 | (i) Calculate the resistance, R, of the lamp. $$R = \frac{V}{I}$$ (ii) Calculate the power supplied to the lamp. (iii) Calculate the amount of energy transferred by the lamp in 40 s.

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A student investigates the resistance of a lamp - Edexcel - GCSE Physics - Question 5 - 2016 - Paper 1

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A student investigates the resistance of a lamp. She obtains these readings for the potential difference (voltage) across the lamp and the current in the lamp. | vo... show full transcript

Worked Solution & Example Answer:A student investigates the resistance of a lamp - Edexcel - GCSE Physics - Question 5 - 2016 - Paper 1

Step 1

Calculate the resistance, R, of the lamp.

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Answer

Using the formula for resistance, we have:

$R = \frac{V}{I}$ Substituting the values:

$R = \frac{6.0}{0.40} = 15 \Omega$

Thus, the resistance of the lamp is 15 Ω.

Step 2

Calculate the power supplied to the lamp.

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Answer

The formula for power is given by:

$P = V \times I$ Substituting the known values:

$P = 6.0 \times 0.40 = 2.4 W$

Therefore, the power supplied to the lamp is 2.4 W.

Step 3

Calculate the amount of energy transferred by the lamp in 40 s.

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Answer

To find the energy transferred, we use the equation:

$E = P \times t$ Substituting in the values for power and time:

$E = 2.4 W \times 40 s = 96 J$

Thus, the amount of energy transferred by the lamp in 40 seconds is 96 J.

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