This question is about using the mains electricity supply - Edexcel - GCSE Physics - Question 5 - 2021 - Paper 1

The energy transferred can be calculated using the formula:

$E = I \times V \times t$

Substituting the known values:

$E = 7.4 \times 230 \times 120$

Calculating gives:

$E = 204240 \text{ J (or 204 kJ)}$

Wire X = neutral Wire Y = live

Component Z = fuse

Using the equation:

$\text{input current} \times \text{input voltage} = \text{output current} \times \text{output voltage}$

Substituting the values:

$\text{input current} \times 230 = 2.37 \times 190$

Solving for the input current yields:

$\text{input current} = \frac{2.37 \times 190}{230} = 1.91 \text{ A (approximately)}$