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8) Which of these is the equation for work done? A work done = force ÷ distance moved in direction of force B work done = force × distance moved in direction of force C work done = force ÷ distance moved at right angles to direction of force D work done = force × distance moved at right angles to direction of force (b) A ball has a mass of 0.046 kg - Edexcel - GCSE Physics - Question 8 - 2019 - Paper 1

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8)-Which-of-these-is-the-equation-for-work-done?---A-work-done-=-force-÷-distance-moved-in-direction-of-force---B-work-done-=-force-×-distance-moved-in-direction-of-force---C-work-done-=-force-÷-distance-moved-at-right-angles-to-direction-of-force---D-work-done-=-force-×-distance-moved-at-right-angles-to-direction-of-force----(b)-A-ball-has-a-mass-of-0.046-kg-Edexcel-GCSE Physics-Question 8-2019-Paper 1.png

8) Which of these is the equation for work done? A work done = force ÷ distance moved in direction of force B work done = force × distance moved in direction of ... show full transcript

Worked Solution & Example Answer:8) Which of these is the equation for work done? A work done = force ÷ distance moved in direction of force B work done = force × distance moved in direction of force C work done = force ÷ distance moved at right angles to direction of force D work done = force × distance moved at right angles to direction of force (b) A ball has a mass of 0.046 kg - Edexcel - GCSE Physics - Question 8 - 2019 - Paper 1

Step 1

Which of these is the equation for work done?

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Answer

The correct equation for work done is:

B. work done = force × distance moved in direction of force.

Step 2

(b)(i) Calculate the change in gravitational potential energy when the ball is lifted through a vertical height of 2.05 m.

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Answer

To find the change in gravitational potential energy (ΔGPE), use the formula:

ΔGPE=m×g×hΔGPE = m × g × h

where:

  • m = 0.046 kg (mass of the ball)
  • g = 9.81 m/s² (acceleration due to gravity)
  • h = 2.05 m (height)

Calculating:

ΔGPE=0.046imes9.81imes2.050.928extJΔGPE = 0.046 imes 9.81 imes 2.05 \approx 0.928 ext{ J}

Thus, the change in gravitational potential energy is approximately 0.93 J.

Step 3

(b)(ii) Calculate the kinetic energy of the ball when the speed of the ball is 3.5 m/s.

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Answer

The kinetic energy (KE) can be calculated using the formula:

KE=12mv2KE = \frac{1}{2} mv^2

where:

  • m = 0.046 kg (mass of the ball)
  • v = 3.5 m/s (speed of the ball)

Calculating:

KE=12×0.046×(3.5)20.281extJKE = \frac{1}{2} \times 0.046 \times (3.5)^2 \approx 0.281 ext{ J}

Thus, the kinetic energy of the ball is approximately 0.28 J.

Step 4

(b)(iii) Use Figure 15 to estimate the maximum height that the ball reaches after the first bounce.

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Answer

From Figure 15, the estimated maximum height of the ball after the first bounce is approximately 1.5 m.

Step 5

(b)(iv) Explain why the ball does not bounce back to its starting height of 2.05 m.

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Answer

The ball does not bounce back to its starting height of 2.05 m due to energy losses during the bounce. Factors such as:

  • Air resistance
  • Deformation of the ball and the surface
  • Dissipation of energy as heat

These factors convert some of the potential energy into other forms, resulting in a lower rebound height.

Step 6

(c) Describe how the maximum height reached changes with the bounce number in Figure 16.

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Answer

Observing Figure 16, the maximum height reached after each bounce decreases progressively as the bounce number increases. This trend indicates that with each successive bounce, the ball loses more energy, likely due to inelastic collisions and energy dissipation, resulting in a lower apex height.

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