6 (a) The symbol 'g' can be used to refer to the acceleration due to gravity - Edexcel - GCSE Physics - Question 6 - 2018 - Paper 1
Question 6
6 (a) The symbol 'g' can be used to refer to the acceleration due to gravity.
The acceleration due to gravity 'g' has the unit of m/s².
'g' can also have another u... show full transcript
Worked Solution & Example Answer:6 (a) The symbol 'g' can be used to refer to the acceleration due to gravity - Edexcel - GCSE Physics - Question 6 - 2018 - Paper 1
Step 1
Which of these is also a unit for g?
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Answer
The correct answer is C N/kg. To understand why, we consider that acceleration is defined as force per unit mass. Therefore, the unit of force is Newton (N), and dividing this by mass (kg) gives us N/kg, which is indeed a valid unit for acceleration.
Step 2
Calculate the average value of time t to an appropriate number of significant figures.
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Answer
To calculate the average value of time t, we sum the three recorded values:
t = rac{0.74 + 0.69 + 0.81}{3}
Calculating this gives:
t = rac{2.24}{3} = 0.746666...
Rounding this to two significant figures gives an average value of time t = 0.75 s.
Step 3
Explain one way the students could improve their procedure to obtain a more accurate value for g.
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Answer
One way students could improve their procedure is by conducting multiple trials and taking the average of a larger set of measurements. This helps to reduce random errors and provides a more reliable estimate of g.
Step 4
Calculate the deceleration of the car.
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Answer
Using the equation of motion:
v2=u2+2as
where:
v = final velocity = 0 m/s (the car comes to rest),
u = initial velocity = 15 m/s,
a = deceleration (which we want to find),
s = distance = 14 m.
Substituting the known values gives:
0=(15)2+2(a)(14)
Rearranging yields:
2a(14)=−225
Thus:
ightarrow a = -8.04 ext{ m/s}^2$$
The deceleration of the car is approximately 8.04 m/s².