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This question is about energy changes - Edexcel - GCSE Physics - Question 6 - 2021 - Paper 1

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This question is about energy changes. (a) Figure 11 shows a water slide. A person travels from the top to the bottom of the water slide. (i) The mass of the perso... show full transcript

Worked Solution & Example Answer:This question is about energy changes - Edexcel - GCSE Physics - Question 6 - 2021 - Paper 1

Step 1

(i) Calculate the change in gravitational potential energy for the person.

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Answer

To calculate the change in gravitational potential energy (GPE), we use the formula:

ΔGPE=m×g×h\Delta GPE = m \times g \times h

Substituting the given values:

ΔGPE=72 kg×10 N/kg×7.0 m\Delta GPE = 72 \text{ kg} \times 10 \text{ N/kg} \times 7.0 \text{ m}

Calculating this gives:

ΔGPE=72×10×7=5040 J\Delta GPE = 72 \times 10 \times 7 = 5040 \text{ J}

Therefore, the change in gravitational potential energy is 5040 J.

Step 2

(ii) Explain what happens to the energy as the person comes to rest after the end of the water slide.

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Answer

As the person comes to rest after the end of the water slide, the gravitational potential energy converted into kinetic energy while sliding down is dissipated. This energy is transformed mainly into thermal energy due to friction with the water and air resistance, and it may also generate sound energy. Thus, the energy does not disappear but is transferred to the surroundings.

Step 3

(b) Explain which one of the three distances shown in Figure 12 should be used to calculate the work done against the force of friction between the box and the slope.

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Answer

To calculate the work done against the force of friction, the distance moved along the slope should be used. This distance represents the path over which the force of friction acts. The horizontal or vertical distances would not account for the work done due to the frictional force acting along the slope.

Step 4

(c) Calculate the kinetic energy of a tennis ball travelling at 28 m/s.

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Answer

First, we need to convert the mass of the tennis ball from grams to kilograms:

m=58 g=0.058 kgm = 58 \text{ g} = 0.058 \text{ kg}

The formula for kinetic energy (KE) is:

KE=12mv2KE = \frac{1}{2} m v^2

Substituting in the values:

KE=12×0.058 kg×(28 m/s)2KE = \frac{1}{2} \times 0.058 \text{ kg} \times (28 \text{ m/s})^2

Calculating this:

KE=0.029×784=22.736 JKE = 0.029 \times 784 = 22.736 \text{ J}

Therefore, the kinetic energy of the tennis ball is approximately 22.74 J.

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