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10 (a) (i) Which lens is a converging lens with the greatest power? A B C D (ii) The equation that relates the power of a lens to the focal length of the lens is power (in dioptres) = 1 focal length (in metres) The power of a lens is 5 dioptres - Edexcel - GCSE Physics - Question 10 - 2019 - Paper 1

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10-(a)-(i)-Which-lens-is-a-converging-lens-with-the-greatest-power?--A-B-C-D--(ii)-The-equation-that-relates-the-power-of-a-lens-to-the-focal-length-of-the-lens-is--power-(in-dioptres)-=-1------------------focal-length-(in-metres)--The-power-of-a-lens-is-5-dioptres-Edexcel-GCSE Physics-Question 10-2019-Paper 1.png

10 (a) (i) Which lens is a converging lens with the greatest power? A B C D (ii) The equation that relates the power of a lens to the focal length of the lens is ... show full transcript

Worked Solution & Example Answer:10 (a) (i) Which lens is a converging lens with the greatest power? A B C D (ii) The equation that relates the power of a lens to the focal length of the lens is power (in dioptres) = 1 focal length (in metres) The power of a lens is 5 dioptres - Edexcel - GCSE Physics - Question 10 - 2019 - Paper 1

Step 1

Which lens is a converging lens with the greatest power?

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Answer

To determine which lens is a converging lens with the greatest power, we need to identify the lens shape that allows parallel rays of light to converge at a focal point. Typically, a converging lens will be thicker in the middle compared to the edges. Based on the characteristics of converging lenses, Lens B appears to have the greatest curvature and thus would be the lens with the highest power.

Step 2

Use the equation to calculate the focal length of the lens in cm.

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Answer

Given the power of the lens (P) is 5 dioptres, we can use the formula:

P = rac{1}{f}

where:

  • P is the power in dioptres,
  • f is the focal length in metres.

From this, we can rearrange the formula to find the focal length:

f = rac{1}{P}

Substituting the value of power:

f = rac{1}{5} = 0.2 ext{ metres}

To convert this into centimetres, we multiply by 100:

f=0.2imes100=20extcmf = 0.2 imes 100 = 20 ext{ cm}

Thus, the focal length of the lens is 20 cm.

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