10 (a) Stars may originate as a nebula - Edexcel - GCSE Physics - Question 10 - 2019 - Paper 1

Using the equation for energy-mass equivalence, we can rearrange it as follows:

$m = \frac{E}{c^2}$

Substituting the given values:

• $E = 3.86 \times 10^{26}$ J
• $c = 3.00 \times 10^{8}$ m/s

We calculate:

$m = \frac{3.86 \times 10^{26} \text{ J}}{(3.00 \times 10^{8} \text{ m/s})^2}$

Calculating the denominator:

$(3.00 \times 10^{8})^2 = 9.00 \times 10^{16} \text{ m}^2/ ext{s}^2$

Thus,

$m = \frac{3.86 \times 10^{26}}{9.00 \times 10^{16}} \approx 4.29 \times 10^9 \text{ kg}$

Therefore, the loss in mass of the Sun in 1 second is approximately $4.29 \times 10^{9}$ kg.