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Question 6
Figure 10 shows an arrangement of gears. Each gear turns around a fixed axle. Gear P is turned through one complete revolution per second. Which of the following de... show full transcript
Step 1
Answer
To solve this, we first analyze the gear ratios. Gear P has 40 teeth and gear R has 20 teeth. When gear P makes one complete revolution, gear R will rotate as follows:
Using the gear ratio: [ \text{Gear Ratio} = \frac{\text{Teeth of P}}{\text{Teeth of R}} = \frac{40}{20} = 2 ]
This means that for every revolution of gear P, gear R turns 2 revolutions. Moreover, the direction of rotation will be opposite to that of gear P.
Thus, the correct answer is C: ( \text{speed (revolutions per second)} = 2, \text{direction of rotation} = \text{opposite to P} ).
Step 2
Answer
To find out how far the rack moves, we use the number of teeth on gear P (10 teeth) and gear Q (40 teeth). Each complete revolution of gear P moves the rack through the distance of the teeth on gear Q.
The distance moved can be calculated as follows:
The distance moved by the rack for 1 revolution of gear P: [ \text{Distance} = \text{Circumference of gear P} \times \left(\frac{\text{Teeth of P}}{\text{Teeth of Q}}\right) ]
distance = 2 mm (as there are 2 mm between the teeth on the rack). Thus, the distance moved by the rack is 10 mm.
Step 3
Answer
We will use the principle of moments about the point where the rod is attached to the ceiling.
Taking moments about the center:
Setting up the equation: [ m \times 17 = (6.0 \times 15) + (4.6 \times 10) ]
Solving for m, we get: [ m = \frac{90 + 46}{17} = 8 g ]
Thus, the mass of the toy elephant is 8.0 g.
Step 4
Answer
To understand the relationship between force K and force L, we can use the principle of hydraulics.
Since the area of piston Y is less than the area of piston Z, we can express the pressures: [ P = \frac{F}{A} ]
Thus, the pressure exerted on piston Y should equal that on piston Z.
In summary, because the area of piston Z is greater, the force required to balance the system under the same pressure conditions varies, making force K less than force L.
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