7. (a) Which of these is a unit of momentum?
A kg/m/s
B kg/m/s
C kg/m/s²
D kg/m/s²
(b) Students investigate conservation of momentum using two identical trolleys - Edexcel - GCSE Physics - Question 7 - 2022 - Paper 1
Question 7
7. (a) Which of these is a unit of momentum?
A kg/m/s
B kg/m/s
C kg/m/s²
D kg/m/s²
(b) Students investigate conservation of momentum using two identical trolle... show full transcript
Worked Solution & Example Answer:7. (a) Which of these is a unit of momentum?
A kg/m/s
B kg/m/s
C kg/m/s²
D kg/m/s²
(b) Students investigate conservation of momentum using two identical trolleys - Edexcel - GCSE Physics - Question 7 - 2022 - Paper 1
Step 1
Which of these is a unit of momentum?
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Answer
The correct answer is A, kg m/s. This is the unit of momentum derived from the formula momentum = mass × velocity.
Step 2
Describe an investigation the students could carry out to show that momentum is conserved when these two trolleys collide.
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Answer
To investigate momentum conservation, set up the two identical trolleys on a frictionless runway. Ensure the trolleys are released from rest. Attach a card to one trolley and use a light gate to measure the velocity before and after the collision. Record the masses and speeds of both trolleys before and after the collision. Use the principle of conservation of momentum, which states that the total momentum before the collision equals the total momentum after the collision.
Step 3
Give a reason for the runway being at a slope.
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Answer
The slope of the runway helps to compensate for the effects of friction, allowing trolley A to travel at a constant speed without slowing down.
Step 4
Calculate the average force exerted by the ball on the racket.
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Answer
First, we need to find the change in momentum:
Initial momentum (mu) = mass × initial velocity = 0.075 kg × 8.2 m/s = 0.615 kg m/s
Final momentum (mv) = mass × final velocity = 0.075 kg × (-15 m/s) = -1.125 kg m/s
Change in momentum = mv - mu = -1.125 kg m/s - 0.615 kg m/s = -1.740 kg m/s.
Now, convert the time (12 ms) to seconds: t = 12 ms = 0.012 s.
Using the formula:
F = (change in momentum) / t = -1.740 kg m/s / 0.012 s = -145.0 N.
The average force exerted by the ball on the racket is approximately 145 N in the direction opposite to the ball's incoming velocity.
Step 5
Describe how Newton's Third Law of Motion applies to the collision between the racket and the ball.
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Answer
Newton's Third Law of Motion states that for every action, there is an equal and opposite reaction. When the ball strikes the racket, it exerts a force on the racket, causing it to change direction and speed. Simultaneously, the racket applies an equal and opposite force on the ball, which is what causes the ball to rebound away from the racket.