A student investigates the resistance of a lamp. She obtains these readings for the potential difference (voltage) across the lamp and the current in the lamp. voltage in V current in A 6.0 0.40 (i) Calculate the resistance, R, of the lamp. R = $ \frac{V}{I} $ (2) (ii) Calculate the power supplied to the lamp. (2) (iii) Calculate the amount of energy transferred by the lamp in 40 s. (2)

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A student investigates the resistance of a lamp - Edexcel - GCSE Physics - Question 5 - 2016 - Paper 1

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A student investigates the resistance of a lamp. She obtains these readings for the potential difference (voltage) across the lamp and the current in the lamp. vol... show full transcript

Worked Solution & Example Answer:A student investigates the resistance of a lamp - Edexcel - GCSE Physics - Question 5 - 2016 - Paper 1

Step 1

Calculate the resistance, R, of the lamp.

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Answer

To find the resistance of the lamp, we use Ohm's law, which states that resistance ( R ) is equal to voltage ( V ) divided by current ( I ):

$R = \frac{V}{I}$

Substituting in the given values:

$R = \frac{6.0 \ V}{0.40 \ A}$

Calculating this yields:

$R = 15 \ \Omega$

Step 2

Calculate the power supplied to the lamp.

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Answer

The power ( P ) supplied to the lamp can be calculated using the formula:

$P = V \times I$

Substituting the known values:

$P = 6.0 \ V \times 0.40 \ A$

Evaluating this gives:

$P = 2.4 \ W$

Step 3

Calculate the amount of energy transferred by the lamp in 40 s.

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Answer

The energy ( E ) transferred by the lamp can be calculated using the formula:

$E = P \times t$

Where ( t ) is the time in seconds. Substituting in the power from part (ii) and the time:

$E = 2.4 \ W \times 40 \ s$

Calculating this gives:

$E = 96 \ J$

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